Anonymous recursion
func fib(n) {
return NaN if (n < 0)
func (n) {
n < 2 ? n
: (__FUNC__(n-1) + __FUNC__(n-2))
}(n)
}func fib(n) {
return NaN if (n < 0)
{|n|
n < 2 ? n
: (__BLOCK__(n-1) + __BLOCK__(n-2))
}(n)
}Last updated