Permutations
Built-in
[0,1,2].permutations { |*a|
say a
}
Iterative
func forperm(callback, n) {
var idx = @^n
loop {
callback(idx...)
var p = n-1
while (idx[p-1] > idx[p]) {--p}
p == 0 && return()
var d = p
idx += idx.splice(p).reverse
while (idx[p-1] > idx[d]) {++d}
idx.swap(p-1, d)
}
return()
}
forperm({|*p| say p }, 3)
Recursive
func permutations(callback, set, perm=[]) {
set || callback(perm)
for i in ^set {
__FUNC__(callback, [
set[^i, i+1 ..^ set.len]
], [perm..., set[i]])
}
return()
}
permutations({|p| say p }, [0,1,2])
Output:
[0, 1, 2]
[0, 2, 1]
[1, 0, 2]
[1, 2, 0]
[2, 0, 1]
[2, 1, 0]
Last updated