Two bullet roulette

unit sub MAIN ($shots = 6);

my @cyl;

sub load () {
    @cyl.=rotate(-1) while @cyl[1];
    @cyl[1] = 1;
    @cyl.=rotate(-1);
}

sub spin () { @cyl.=rotate: (^@cyl).pick }

sub fire () { @cyl.=rotate; @cyl[0] }

sub LSLSFSF {
    @cyl = 0 xx $shots;
    load, spin, load, spin;
    return 1 if fire;
    spin;
    fire
}

sub LSLSFF {
    @cyl = 0 xx $shots;
    load, spin, load, spin;
    fire() || fire
}

sub LLSFSF {
    @cyl = 0 xx $shots;
    load, load, spin;
    return 1 if fire;
    spin;
    fire
}

sub LLSFF {
    @cyl = 0 xx $shots;
    load, load, spin;
    fire() || fire
}

my %revolver;
my $trials = 100000;

for ^$trials {
    %revolver<LSLSFSF> += LSLSFSF;
    %revolver<LSLSFF>  += LSLSFF;
    %revolver<LLSFSF>  += LLSFSF;
    %revolver<LLSFF>   += LLSFF;
}

say "{.fmt('%7s')}: %{(%revolver{$_} / $trials × 100).fmt('%.2f')}"
  for <LSLSFSF LSLSFF LLSFSF LLSFF>

Output:

LSLSFSF: %55.37
 LSLSFF: %58.30
 LLSFSF: %55.42
  LLSFF: %50.29

Though if you go and look at the Wikipedia article for the 1895 Nagant revolver mentioned in the task reference section, you'll see it is actually a 7 shot revolver... so, run again with 7 chambers:

raku roulette.raku 7

LSLSFSF: %49.29
 LSLSFF: %51.14
 LLSFSF: %48.74
  LLSFF: %43.08

Or, how about a Ruger GP100 10 round revolver?

raku roulette.raku 10

LSLSFSF: %36.00
 LSLSFF: %37.00
 LLSFSF: %36.13
  LLSFF: %29.77

Doesn't change the answers, B (LSLSFF) is definitely the worst most likely choice in all cases.