Attractive numbers

This algorithm is concise but not really well suited to finding large quantities of consecutive attractive numbers. It works, but isn't especially speedy. More than a hundred thousand or so gets tedious. There are other, much faster (though more verbose) algorithms that could be used. This algorithm is well suited to finding arbitrary attractive numbers though.

use Lingua::EN::Numbers;
use ntheory:from<Perl5> <factor is_prime>;

sub display ($n,$m) { ($n..$m).grep: (~*).&factor.elems.&is_prime }

sub count ($n,$m) { +($n..$m).grep: (~*).&factor.elems.&is_prime }

# The Task
put "Attractive numbers from 1 to 120:\n" ~
display(1, 120)».fmt("%3d").rotor(20, :partial).join: "\n";

# Robusto!
for 1, 1000,  1, 10000, 1, 100000, 2**73 + 1, 2**73 + 100 -> $a, $b {
    put "\nCount of attractive numbers from {comma $a} to {comma $b}:\n" ~
    comma count $a, $b
}

Output:

Attractive numbers from 1 to 120:
  4   6   8   9  10  12  14  15  18  20  21  22  25  26  27  28  30  32  33  34
 35  38  39  42  44  45  46  48  49  50  51  52  55  57  58  62  63  65  66  68
 69  70  72  74  75  76  77  78  80  82  85  86  87  91  92  93  94  95  98  99
102 105 106 108 110 111 112 114 115 116 117 118 119 120

Count of attractive numbers from 1 to 1,000:
636

Count of attractive numbers from 1 to 10,000:
6,396

Count of attractive numbers from 1 to 100,000:
63,255

Count of attractive numbers from 9,444,732,965,739,290,427,393 to 9,444,732,965,739,290,427,492:
58